Design of Fermentation Processes
385
D
= f > !
D
0.6
3
the transient ends in a new steady state where
_x„
0.8
-0.6 1-0.4
3
Z* ~ x
0
" 0.8 - 0 .4 'l-0.6 ~
4
and
t = 5
If instead of
D
= 0.6 h4, we choose
D~
0.8 h
1
after
t=
0, then
n
= 1 and
t - k 2k
1 ~
5
4
Jco _ 1| +
5
in|JL| =
7
.
5
|f!L-l| + 51n| X
Finally, take
D
= 4/3 h4 , for which
n -
3/5:
(4)
(5)
(
6
)
(7)
Figure 9.7, Simulation of transient experiments in a stirred tank reactor for Monod kinetics. At time
zero, D is changed from 0.4 h
4
to either 0.6, 0.8 or 4/3 h'1.
^ „ = 1
h'!,a =K/sf
=0.25;
X0 =x0/(Ysxsj)
= 5/6.
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